Series 03

Given a number of terms the task is to calculate the value upto ‘n’ terms of the below given series using recursion.

Series: (1/2!) + (2/3!) + (3/4!) + (4/5!) + …………… + ‘n’ terms

Java
import java.util.*;
public class RecSeries
{
    public double getFact(int n)
    {
        if(n==1)
        {
            return 1;
        }
        else
        {
            return n*getFact(n-1);
        }
    }
    public double getSum(int n)
    {
        if(n==0)
        {
            return 0;
        }
        else
        {
            return (n/getFact(n+1))+getSum(n-1);
        }
    }
    public static void main(String args[])
    {
        int n=0;
        double s=0.0;
        Scanner sc=new Scanner(System.in);
        RecSeries ob=new RecSeries();
        System.out.print("Enter number of terms: ");
        n=sc.nextInt();
        s=ob.getSum(n);
        System.out.println("Result: "+s);
    }
}
Java