Series Overload 02 – SchoolCodeHub

Use function overloading to calculate the sum of below given two series.

Series 1: (1/1)+(1/2)+(1/3)+(1/4)+……….+’n’ terms.

Series 2: (1/a²)+(4/a⁵)+(7/a⁸)+(10/a¹¹)+……….+’n’ terms.

Take all required inputs from main functions and invoke the functions using class object.

Java

import java.util.*;
public class SeriesOverload
{
    public void sumSeries(int n)
    {
        double s=0;
        for(int i=1;i<=n;i++)
        {
            s=s+((double)1/i);
        }
        System.out.println("Sum of Series 1: "+s);
    }
    public void sumSeries(int n,int a)
    {
        int c=1;
        double s=0;
        for(int i=1;i<=n;i++)
        {
            s=s+(c/Math.pow(a,(c+1)));
        }
        c=c+3;
        System.out.println("Sum of Series 2: "+s);
    }
    public static void main(String args[])
    {
        int n=0,a=0;
        Scanner sc=new Scanner(System.in);
        SeriesOverload ob=new SeriesOverload();
        System.out.print("Enter a number: ");
        a=sc.nextInt();
        System.out.print("Enter number of terms: ");
        n=sc.nextInt();
        ob.sumSeries(n);
        ob.sumSeries(n,a);
    }
}

Java