Given a number of terms the task is to calculate the value upto ‘n’ terms of the below given series.
Series: 1⁄1 + 1⁄3 + 2⁄5 + 3⁄7 + 4⁄9 + …………… + ‘n’ terms
C
#include <stdio.h>
void main()
{
int n=0;
double result=0.0,c=1.0;
printf("Enter number of terms: ");
scanf("%d",&n);
for(int i=1;i<=n;i++)
{
result=result+(i/c);
c=c+2;
}
printf("Result of the series : %lf",result);
}