Given a number of terms the task is to calculate the value upto ‘n’ terms of the below given series.
Series: 1⁄2 + 2⁄3 + 3⁄4 + 4⁄5 + …………… + ‘n’ terms
C
#include <stdio.h>
void main()
{
int n=0;
double result=0.0;
printf("Enter number of terms: ");
scanf("%d",&n);
for(int i=1;i<=n;i++)
{
result=result+(double)i/(i+1);
}
printf("Result of the series: %lf",result);
}