Given a number the task is to find the number of even digits present in the number.
Example 1: Let us take a numberĀ 58162. Here number of even digits is 3.
C
#include <stdio.h>
int main()
{
int n=0,r=0,count=0;
printf("Enter a number: ");
scanf("%d",&n);
while(n>0)
{
r=n%10;
if(r%2==0)
{
count++;
}
n=n/10;
}
printf("Number of Even digit: %d",count);
return 0;
}C