Given a starting number and the ending number the task is to find the all the Adam Number present in that given range and also to display it’s frequency.
Adam Number is a number whose square of the number and square of it’s reverse are reverse to each other.
Example 1: 12. Here 122 = 144 and 212 = 441. We observe that the square of 12 and the square of it’s reverse i.e. 21 are reverse of each other. Thus 12 is an Adam Number.
Java
import java.util.*;
public class AdamNumberRange
{
public static void main(String args[])
{
int start=0,end=0,r=0,rev=0,temp=0,frequency=0;
Scanner sc=new Scanner(System.in);
System.out.print("Enter a starting range: ");
start=sc.nextInt();
System.out.print("Enter a ending range: ");
end=sc.nextInt();
System.out.println("Adam Numbers in the given range are:-");
for(int i=start;i<=end;i++)
{
temp=i;
while(temp>0)
{
r=temp%10;
rev=(rev*10)+r;
temp=temp/10;
}
temp=rev*rev;
rev=0;
while(temp>0)
{
r=temp%10;
rev=(rev*10)+r;
temp=temp/10;
}
if(rev==(i*i))
{
System.out.println(i);
frequency++;
}
rev=0;
}
System.out.println("Frequency: "+frequency);
}
}